Algebra
Essay by Shraya Patel • November 1, 2017 • Term Paper • 608 Words (3 Pages) • 1,250 Views
Number
Achievement Criteria | Q | Evidence | Code | ✓ | Judgement | Sufficiency | |||
Achievement | Solve number problems. | 1 | 0.18, 19%, [pic 1], 35%, [pic 2], 0.39 | A A | ✓ ✓✓ | Award 1 ‘A’ if there is 1 mistake. | 5 A | ||
2 |
| A A | ✓ ✓ | Accept sensible rounding | |||||
3(a) | $64.50 | A | ✓ | ||||||
3(b) | 53.5 Euro | A | ✓ | Accept 53 or 54 | |||||
3(c) | 399.1 Rand | A | ✓ | Accept 399 | |||||
3(d) | $ 125 Singapore | A | ✓ | ||||||
Merit | Solve number problems in context. | 4(a) | 3.822 × 1021 | M | ✓ ✓ | Number Standard form | Achievement plus 4 M | ||
4(b) | 4.9156 × 1012 | M | ✓ ✓ | Number Standard form | |||||
4(c) | 4.89922 × 1012 | M | ✓ ✓ | Number Standard form | |||||
5 | $149.00 | M | ✓ working ✓ answer | ||||||
6(a) | Least 10.35 Most 10.45 | M | ✓ ✓ | Accept 10.35 ≤ t < 10.45 | |||||
6(b) | Least 99m 95cm Most 100m 5 cm | M | ✓ ✓ | Accept 99.95 ≤ d < 100.05 | |||||
7 | 21.3 g (21.28125) | M | ✓ working ✓ answer ✓ rounding | ||||||
Excellence | Solve number problems in context involving several steps or reversing processes. | 8 | 14 cm × 21 cm × 42 cm | E | ✓ ✓ ✓ | Merit plus 2 E | |||
9 | Amount available: 2500 × 0.95 2375 mL Bottles filled: 2375 ÷ 200 11 (11.875) Need to charge: 35 × 1.4 ÷ 11 $4.45 (4.45454545…) | E | ✓ ✓ ✓ ✓ ✓ | Must be supported by working, including annotations stating what is being calculated. |
Geometry
Achievement Criteria | Q | Evidence | Code | ✓ | Judgement | Sufficiency | |
Achievement | Solve simple angle problems and give reasons. | 1 | f = 110° B = 55° g = 55° | A A A | Each ✓ angle ✓ reason | Reasons not required. Do not award if reason is isosceles triangle. | 4 A |
2 | p = 108° q = 72° r = 72° | A A A | Each ✓ angle ✓ reason | Reasons not required. | |||
Merit | Solve angle problems and give reasons. | 3(a) | Isosceles | M | ✓ | Achievement plus 2 M | |
3(b) | [pic 3][pic 4] [pic 5][pic 6][pic 7] | M | ✓ angles ✓ sides | Both correct. | |||
4(a) | 90o Square | M | ✓ both | (a) and (b) plus one of (c) and (d) | |||
4(b) | 60o Equilateral triangle | ✓ both | |||||
4(c) | 15o Isosceles triangle | ✓ angle ✓ reason | |||||
4(d) | 30o Square | ✓ angle ✓ reason | |||||
Excellence | Calculate angles giving reasons. | 5 | a = 90o b = 85o c = 85o d = 47o | E | Each ✓ angle ✓ reason | Reasons depend on order. ALL angles and reasons correct. | Merit E |
Graphs
Achievement Criteria | Q | Evidence | Code | ✓ | Judgement | Sufficiency | |||||||||
Achievement | Plot and Interpret simple linear graphs | 1(a) | $70 | A | ✓ | 3 A | |||||||||
1(b) | 2 hours | A | ✓ | ||||||||||||
1(c) |
| A | ✓ | All correct | |||||||||||
1(d) | Line starts at $15 and intersects PHHP line at 2 hours | A | ✓ | ||||||||||||
Merit | Write equations of simple linear graphs. Draw simple parabolas | 1(e) | C = 20H + 15 | M1 | ✓ | Must be equation (with =) | Achieved plus 3 M1 and 1 M2 | ||||||||
1(f) | Two points: 1. Same price for 2 hours. 2. HHHC cheaper for <2 hours 3. PHHP cheaper for >2 hours | M1 | ✓✓ One for each point | Must have 2 points | |||||||||||
2(a) | y = 3x + 3 | M1 | ✓ | Must be equations (with =) | |||||||||||
2(b) | x = 2 | M1 | ✓ | ||||||||||||
2(c) | y = -x – 1[pic 8][pic 9] | M1 | ✓ | ||||||||||||
3(a) | [pic 10] | M2 | ✓ | ||||||||||||
3(b) | M2 | ✓ | |||||||||||||
Excellence | Write equations of parabolas | 4 | y = (x-1)(x-3) or | E | ✓ | Oops. Sorry this is the same as 3(a)!!! | Merit plus E |
Algebra
Achievement Criteria | Q | Evidence | Code | ✓ | Judgement | Sufficiency | |
Achievement | Carry out simple algebraic manipulations (A1). Solve straightforward algebraic equations (A2). Describe simple arithmetic or geometric patterns (A2). | 1(a) | 8r | A1 | ✓ | No alternative | 4 A1 plus both A2 both A3 |
1(b) | 13x - 5z | A1 | ✓ | Or equivalent | |||
1(c) | a5 | A1 | ✓ | No alternative | |||
1(d) | b4 | A1 | ✓ | No alternative | |||
2(a) | 3x + 18 | A1 | ✓ | Or equivalent | |||
2(b) | 8x2 + 4x | A1 | ✓ | Or equivalent | |||
3(a) | x = 3 | A2 | ✓ | ||||
3(b) | x = 7 | A2 | ✓ | ||||
4(a) | [pic 11] | A3 | ✓ | ||||
4(b) | 13 16 19 | A3 | ✓ | ALL | |||
Merit | Find terms and rules for patterns (M1). Carry out more complex algebraic manipulations (M2). Solve equations (M3). Interpret linear graphs (M4). | 4(c) | L = 3F + 1 | M1 | ✓ | Achievement Plus 2 M1 6 M2 3 M3 3 M4 Replacement M2 for A1 M3 for A2 M1 for A3 | |
4(d) | 67 | M1 | ✓ | ||||
4(e) | 51 | M1 | ✓ | ||||
5(a) | 6 | M2 | Working ✓ Answer ✓ | No alternative | |||
5(b) | 50 | M2 | Working ✓ Answer ✓ | No alternative | |||
6 | p4 | M2 | ✓ | No alternative | |||
7(a) | 9x - 4 | M2 | Expand ✓ Simplify ✓ | Or equivalent | |||
7(b) | x2 + 3x - 10 | M2 | Expand ✓ Simplify ✓ | Or equivalent | |||
7(c) | 6x2 - x - 35 | M2 | Expand ✓ Simplify ✓ | Or equivalent | |||
8(a) | 2(x + 4) | M2 | ✓ | No alternative | |||
8(c) | (x + 2)(x + 9) | M2 | (x + 2)✓ (x + 9)✓ | ||||
9(a) | x = 1.5 | M3 | Working ✓ Answer ✓ | Or equivalent | |||
9(b) | x = 9 | M3 | Working ✓ Answer ✓ | No alternative | |||
10(a) | 90 - 8x | M3 | ✓✓ | Or equivalent | |||
10(b) | (30 - 2x)(15 - 2x) | M3 | ✓✓ | Or equivalent | |||
12(a) | $ 15.20 | M4 | Working ✓ Answer ✓ | ||||
Excellence | Solve algebra problems using graphs and manipulation. | 12(b) | Cook for 40 minutes per kg | E | ✓ | Merit plus 2 E | |
12(c) | [pic 12] | ✓✓ | Or equivalent | ||||
12(d) | 8.5 kg | ✓✓ | |||||
13 | (4x + 7)(4x - 7) | E | (4x + 7)✓ (4x - 7)✓ | ||||
15 | x + (x + 10) + 3(x + 10) = 65 5x + 40 = 65 5x = 25 x = 5 Numbers are 5, 15 and 45 | E | ✓ ✓ ✓ ✓ |
Trigonometry
Achievement Criteria | Q | Evidence | Code | ✓ | Judgement | Sufficiency | |
Achievement | Find simple, unknown lengths of right-angled triangles from diagrams using trig ratios and Pythagoras. | 1 | 7.2 cm (7.211102551) | A | working ✓ answer ✓ | 3 A | |
2 | 1.43m | A | ✓ | ||||
3(a) | 8.7 km (8.693332437) | A | working ✓ answer ✓ | ||||
3(b) | 2.3 km (2.329371406) | A | working ✓ answer ✓ | ||||
Merit | Find unknowns of right-angled triangles from words and diagrams using trig ratios and Pythagoras. | 4 | 29.7o (29.7448813) | M | working ✓ answer ✓ | Achievement plus 2 M | |
5(a) | 26.9 cm (26.92582404) | M | working ✓ answer ✓ | ||||
5(b) | 21.8o (21.80140949) | M | working ✓ answer ✓ | ||||
Excellence | Model complex situations to find unknowns of a right-angled triangle using Pythagoras or trig ratios | 6 | 45.2o (45.2397299) | E | working ✓ 22.6 ✓ doubling ✓ | Merit plus 2 E | |
7(a) | 8.8 cm (8.774964387) | E | working ✓ answer ✓ | ||||
7(b) | 27.1o (27.11914277) | E | working ✓ answer ✓ |
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